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七年级数学solution一般
题目
已知A=2a2+3ab2a1A=2a^{2}+3ab-2a-1,B=a2+ab+2B=-a^{2}+ab+2.化简:4A(3A2B)4A-\left(3A-2B\right).
知识点:代数式求值、整式加减运算法则章节:未标注

答案与解析

答案

A=2a2+3ab2a1\because A=2a^{2}+3ab-2a-1B=a2+ab+2B=-a^{2}+ab+2
4A(3A2B)\therefore 4A-\left(3A-2B\right)
=4A3A+2B=4A-3A+2B
=A+2B=A+2B
=(2a2+3ab2a1)+2(a2+ab+2)=(2a^{2}+3ab-2a-1)+2(-a^{2}+ab+2)
=2a2+3ab2a12a2+2ab+4=2a^{2}+3ab-2a-1-2a^{2}+2ab+4
=5ab2a+3=5ab-2a+3.

解析

A=2a2+3ab2a1\because A=2a^{2}+3ab-2a-1B=a2+ab+2B=-a^{2}+ab+2
4A(3A2B)\therefore 4A-\left(3A-2B\right)
=4A3A+2B=4A-3A+2B
=A+2B=A+2B
=(2a2+3ab2a1)+2(a2+ab+2)=(2a^{2}+3ab-2a-1)+2(-a^{2}+ab+2)
=2a2+3ab2a12a2+2ab+4=2a^{2}+3ab-2a-1-2a^{2}+2ab+4
=5ab2a+3=5ab-2a+3.

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