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七年级数学解答题一般
题目
请把下列各数填入相应的集合中.
33,23\frac{2}{3},00,227\frac{22}{7},3.14-3.14,2020,(+5)-\left(+5\right),+1.88+1.88,22-2^{2}.
(1)(1)负数集合:{______}\{\_\_\_\_\_\_\ldots \}
(2)(2)整数集合:{______}\{\_\_\_\_\_\_\ldots \}
(3)(3)分数集合:{______}.\{\_\_\_\_\_\_\ldots \}.
知识点:正数与负数章节:第1章 有理数 / 1.1 正数和负数

答案与解析

答案

(1)(+5)=5\left(1\right)-\left(+5\right)=-522=4-2^{2}=-4
负数集合:{3.14,(+5)\{-3.14,-\left(+5\right)22}-2^{2}\ldots \}
(2)(2)整数集合:{3,0,20,(+5)\{3,0,20,-\left(+5\right)22}-2^{2}\ldots \}
(3)(3)分数集合:{232273.14+1.88}\{\frac{2}{3},\frac{22}{7},-3.14,+1.88\ldots \}.
故答案为:(1)3.14\left(1\right)-3.14(+5)-\left(+5\right)22-2^{2}(2)3\left(2\right)3002020(+5)-\left(+5\right)22-2^{2}(3)232273.14+1.88\left(3\right)\frac{2}{3},\frac{22}{7},-3.14,+1.88.

解析

(1)(+5)=5\left(1\right)-\left(+5\right)=-522=4-2^{2}=-4
负数集合:{3.14,(+5)\{-3.14,-\left(+5\right)22}-2^{2}\ldots \}
(2)(2)整数集合:{3,0,20,(+5)\{3,0,20,-\left(+5\right)22}-2^{2}\ldots \}
(3)(3)分数集合:{232273.14+1.88}\{\frac{2}{3},\frac{22}{7},-3.14,+1.88\ldots \}.
故答案为:(1)3.14\left(1\right)-3.14(+5)-\left(+5\right)22-2^{2}(2)3\left(2\right)3002020(+5)-\left(+5\right)22-2^{2}(3)232273.14+1.88\left(3\right)\frac{2}{3},\frac{22}{7},-3.14,+1.88.

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