题目如图,点EEE在CDCDCD上,BCBCBC与AEAEAE交于点FFF,AB=CBAB=CBAB=CB,BE=BDBE=BDBE=BD,∠1=∠2\angle 1=\angle 2∠1=∠2.(1)(1)(1)求证:AE=CDAE=CDAE=CD;(2)(2)(2)证明:∠1=∠3\angle 1=\angle 3∠1=∠3.知识点:勾股定理、垂径定理、解直角三角形章节:未标注