题目如图,在△ABC\triangle ABC△ABC中,∠ACB=90∘\angle ACB=90^{\circ}∠ACB=90∘,∠B=30∘\angle B=30^{\circ}∠B=30∘,BC=43BC=4\sqrt{3}BC=43,点PPP是直角边BCBCBC上一动点(点PPP不与BBB,CCC重合),连接APAPAP,将线段APAPAP绕点AAA顺时针旋转60∘60^{\circ}60∘得线段ADADAD,连接CDCDCD,则线段CDCDCD的最小值是______.知识点:图形的旋转章节:未标注