题目如图,在△ABC\triangle ABC△ABC中,AB=BCAB=BCAB=BC,tan∠B=512\tan \angle B=\frac{5}{12}tan∠B=125,DDD为BCBCBC上一点,若满足CD=35BDCD=\frac{3}{5}BDCD=53BD,过DDD作DE⊥ADDE\bot ADDE⊥AD交ACACAC延长线于点EEE,则CEAC=______.\frac{CE}{AC}=\_\_\_\_\_\_.ACCE=______.知识点：勾股定理章节：未标注
如图,在中,,,为上一点,若满足,过作交延长线于点,则如图,在中,,,为上一点,若满足,过作交延长线于点,则如图,在中,,,为上一点,若满足,过作交延长线于点,则