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七年级数学solution一般
题目
计算:42022×(0.25)2023=______.4^{2022}\times \left(-0.25\right)^{2023}=\_\_\_\_\_\_.
知识点:有理数的乘方(二)、幂的乘方与积的乘方章节:未标注

答案与解析

答案

42022×(0.25)20234^{2022}\times \left(-0.25\right)^{2023}
=42022×(0.25)2022×(0.25)=4^{2022}\times \left(-0.25\right)^{2022}\times \left(-0.25\right)
=(4×0.25)2022×(0.25)=\left(-4\times 0.25\right)^{2022}\times \left(-0.25\right)
=(1)2022×(0.25)=\left(-1\right)^{2022}\times \left(-0.25\right)
=0.25=-0.25.
故答案为:0.25-0.25.

解析

42022×(0.25)20234^{2022}\times \left(-0.25\right)^{2023}
=42022×(0.25)2022×(0.25)=4^{2022}\times \left(-0.25\right)^{2022}\times \left(-0.25\right)
=(4×0.25)2022×(0.25)=\left(-4\times 0.25\right)^{2022}\times \left(-0.25\right)
=(1)2022×(0.25)=\left(-1\right)^{2022}\times \left(-0.25\right)
=0.25=-0.25.
故答案为:0.25-0.25.

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