题目如图,在△ABC\triangle ABC△ABC中,∠C=90∘\angle C=90^{\circ}∠C=90∘,ADADAD是∠BAC\angle BAC∠BAC的平分线,DE⊥ABDE\bot ABDE⊥AB于点EEE,点FFF在ACACAC上,BD=DFBD=DFBD=DF.证明:(1)CF=EB(1)CF=EB(1)CF=EB;(2)AB=AF+2EB(2)AB=AF+2EB(2)AB=AF+2EB.知识点:全等三角形的判定章节:未标注