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八年级数学solution一般
题目
如图,ABC\triangle ABC中,ADBCAD\bot BCDD,要使ABD\triangle ABDACD\triangle ACD,若根据"HLHL"判定,还需要加条件______.
知识点:直角三角形全等的判定章节:未标注

答案与解析

答案

还需添加条件AB=ACAB=AC
ADBC\because AD\bot BCDD
ADB=ADC=90\therefore \angle ADB=\angle ADC=90^{\circ}
RtABDRt\triangle ABDRtACDRt\triangle ACD中,
{AB=ACAD=AD\left\{\begin{array}{l}{AB=AC}\\{AD=AD}\end{array}\right.
RtABD\therefore Rt\triangle ABDRtACD(HL)Rt\triangle ACD\left(HL\right)
故答案为:AB=ACAB=AC.

解析

还需添加条件AB=ACAB=AC
ADBC\because AD\bot BCDD
ADB=ADC=90\therefore \angle ADB=\angle ADC=90^{\circ}
RtABDRt\triangle ABDRtACDRt\triangle ACD中,
{AB=ACAD=AD\left\{\begin{array}{l}{AB=AC}\\{AD=AD}\end{array}\right.
RtABD\therefore Rt\triangle ABDRtACD(HL)Rt\triangle ACD\left(HL\right)
故答案为:AB=ACAB=AC.

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