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八年级数学solution一般
题目
如图,若AB=ADAB=AD,加上一个条件______,,则有ABC\triangle ABCADC.\triangle ADC.
知识点:全等三角形的判定章节:未标注

答案与解析

答案

BC=DCBC=DC时,
ABC\triangle ABCADC\triangle ADC
{AB=ADAC=ACBC=CD\because \left\{\begin{array}{l}{AB=AD}\\{AC=AC}\\{BC=CD}\end{array}\right.
ABC\therefore \triangle ABCADC(SSS).\triangle ADC\left(SSS\right).
故答案为:BC=DCBC=DC.

解析

BC=DCBC=DC时,
ABC\triangle ABCADC\triangle ADC
{AB=ADAC=ACBC=CD\because \left\{\begin{array}{l}{AB=AD}\\{AC=AC}\\{BC=CD}\end{array}\right.
ABC\therefore \triangle ABCADC(SSS).\triangle ADC\left(SSS\right).
故答案为:BC=DCBC=DC.

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