题目如图,在△ABC\triangle ABC△ABC中,CA=CBCA=CBCA=CB,∠ACB=90∘\angle ACB=90^{\circ}∠ACB=90∘,ADADAD平分∠BAC\angle BAC∠BAC,BE⊥ADBE\bot ADBE⊥AD,交ADADAD的延长线于点EEE.若BE=254BE=\frac{25}{4}BE=425,则ADADAD的长为______.知识点:三角形内角和定理章节:未标注