题目将抛物线y=x2+2y=x^{2}+2y=x2+2先向左平移222个单位,再向下平移111个单位,得到的新抛物线的解析式（ ）A.y=(x−1)2+4y=\left(x-1\right)^{2}+4y=(x−1)2+4B.y=(x+1)2+4y=\left(x+1\right)^{2}+4y=(x+1)2+4C.y=(x−2)2+1y=\left(x-2\right)^{2}+1y=(x−2)2+1D.y=(x+2)2+1y=\left(x+2\right)^{2}+1y=(x+2)2+1知识点：二次函数章节：未标注
