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七年级数学解答题一般
题目
把下列各数分别填入相应的集合里.
13\frac{1}{3},0.50.5,+7+7,00,6.4-6.4,200%200\%,(+26)-\left(+26\right),1.010010011.01001001\ldots \ldots
负数集合:{______}\{ \_\_\_\_\_\_\ldots \}
整数集合:{______}\{ \_\_\_\_\_\_\ldots \}
分数集合:{______}\{ \_\_\_\_\_\_\ldots \}
非负有理数:{______}.\{ \_\_\_\_\_\_\ldots \}.
知识点:绝对值(二)章节:第1章 有理数 / 1.2 有理数 / 1.2.4 绝对值

答案与解析

答案

(+26)=26-\left(+26\right)=-26200%=2200\%=2
负数集合:{6.4,(+26)}\{-6.4,-\left(+26\right)\}
整数集合:{+7,0,(+26),200%}\{+7,0,-\left(+26\right),200\%\}
分数集合:{13\{\frac{1}{3}0.5,6.4,1.01001001}0.5,-6.4,1.01001001\ldots \ldots \}
非负有理数:{13\{\frac{1}{3}0.5,+7,0,200%,1.01001001}0.5,+7,0,200\%,1.01001001\ldots \ldots \}.
故答案为:6.4-6.4(+26)-\left(+26\right)+7+700(+26)-\left(+26\right)200%200\%13\frac{1}{3}0.50.56.4-6.41.010010011.01001001\ldots \ldots13\frac{1}{3}0.50.5+7+700200%200\%1.010010011.01001001\ldots \ldots.

解析

(+26)=26-\left(+26\right)=-26200%=2200\%=2
负数集合:{6.4,(+26)}\{-6.4,-\left(+26\right)\}
整数集合:{+7,0,(+26),200%}\{+7,0,-\left(+26\right),200\%\}
分数集合:{13\{\frac{1}{3}0.5,6.4,1.01001001}0.5,-6.4,1.01001001\ldots \ldots \}
非负有理数:{13\{\frac{1}{3}0.5,+7,0,200%,1.01001001}0.5,+7,0,200\%,1.01001001\ldots \ldots \}.
故答案为:6.4-6.4(+26)-\left(+26\right)+7+700(+26)-\left(+26\right)200%200\%13\frac{1}{3}0.50.56.4-6.41.010010011.01001001\ldots \ldots13\frac{1}{3}0.50.5+7+700200%200\%1.010010011.01001001\ldots \ldots.

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