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七年级数学解答题一般
题目
把下列各数填入它所属的集合内:
5.25.2,00,π2\frac{π}{2},227\frac{{22}}{7},+(4)+\left(-4\right),234-2\frac{3}{4},(3)-\left(-3\right),0.255550.25555,0.03%-0.03\%
(1)(1)自然数集合:{______}\{ \_\_\_\_\_\_\ldots \ldots \}
(2)(2)分数集合:{______}\{ \_\_\_\_\_\_\ldots \ldots \}
(3)(3)有理数集合:{______}.\{ \_\_\_\_\_\_\ldots \ldots \}.
知识点:绝对值(二)章节:第1章 有理数 / 1.2 有理数 / 1.2.4 绝对值

答案与解析

答案

(1)自然数集合:{0,(3)}\{0,-\left(-3\right)\ldots \ldots \}
(2)(2)分数集合:{5.2\{ 5.2227\frac{{22}}{7}234-2\frac{3}{4}0.25555,0.03%}0.25555,-0.03\%\ldots \ldots \}
(3)(3)有理数集合:{5.2\{ 5.200227\frac{{22}}{7}+(4)+\left(-4\right)234-2\frac{3}{4}(3),0.25555,0.03%}-\left(-3\right),0.25555,-0.03\%\ldots \ldots \}.
故答案为:00(3)-\left(-3\right)5.25.2227\frac{{22}}{7}234-2\frac{3}{4}0.255550.255550.03%-0.03\%5.25.200227\frac{{22}}{7}+(4)+\left(-4\right)234-2\frac{3}{4}(3)-\left(-3\right)0.255550.255550.03%-0.03\%.

解析

(1)自然数集合:{0,(3)}\{0,-\left(-3\right)\ldots \ldots \}
(2)(2)分数集合:{5.2\{ 5.2227\frac{{22}}{7}234-2\frac{3}{4}0.25555,0.03%}0.25555,-0.03\%\ldots \ldots \}
(3)(3)有理数集合:{5.2\{ 5.200227\frac{{22}}{7}+(4)+\left(-4\right)234-2\frac{3}{4}(3),0.25555,0.03%}-\left(-3\right),0.25555,-0.03\%\ldots \ldots \}.
故答案为:00(3)-\left(-3\right)5.25.2227\frac{{22}}{7}234-2\frac{3}{4}0.255550.255550.03%-0.03\%5.25.200227\frac{{22}}{7}+(4)+\left(-4\right)234-2\frac{3}{4}(3)-\left(-3\right)0.255550.255550.03%-0.03\%.

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