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七年级数学解答题一般
题目
把下列各数填在相应的大括号内:
3-3,34-\frac{3}{4},12-12,00,0.120.12,50%50\%,3.14-3.14,1.991.99,+6+6,(3)-\left(-3\right).
(1)(1)正数集合:{______}\{ \_\_\_\_\_\_\ldots \}
(2)(2)负数集合:{______}\{ \_\_\_\_\_\_\ldots \}
(3)(3)分数集合:{______}\{ \_\_\_\_\_\_\ldots \}
(4)(4)整数集合:{______}.\{ \_\_\_\_\_\_\ldots \}.
知识点:正数与负数、绝对值(二)章节:第1章 有理数 / 1.2 有理数 / 1.2.4 绝对值

答案与解析

答案

把下列各数填在相应的大括号内:
3-334-\frac{3}{4}12-12000.120.1250%50\%3.14-3.141.991.99+6+6(3)-\left(-3\right).
(1)(1)正数集合:{0.12,50%,1.99,+6,(3)}\{0.12,50\%,1.99,+6,-\left(-3\right)\ldots \}
(2)(2)负数集合:{3\{-334-\frac{3}{4}12,3.14}-12,-3.14\ldots \}
(3)(3)分数集合:{34\{-\frac{3}{4}0.12,50%,3.14,1.99}0.12,50\%,-3.14,1.99\ldots \}
(4)(4)整数集合:{3,12,0,+6,(3)}\{-3,-12,0,+6,-\left(-3\right)\ldots \}.
故答案为:0.120.1250%50\%1.991.99+6+6(3)-\left(-3\right)3-334-\frac{3}{4}12-123.14-3.1434-\frac{3}{4}0.120.1250%50\%3.14-3.141.991.993-312-1200+6+6(3)-\left(-3\right).

解析

把下列各数填在相应的大括号内:
3-334-\frac{3}{4}12-12000.120.1250%50\%3.14-3.141.991.99+6+6(3)-\left(-3\right).
(1)(1)正数集合:{0.12,50%,1.99,+6,(3)}\{0.12,50\%,1.99,+6,-\left(-3\right)\ldots \}
(2)(2)负数集合:{3\{-334-\frac{3}{4}12,3.14}-12,-3.14\ldots \}
(3)(3)分数集合:{34\{-\frac{3}{4}0.12,50%,3.14,1.99}0.12,50\%,-3.14,1.99\ldots \}
(4)(4)整数集合:{3,12,0,+6,(3)}\{-3,-12,0,+6,-\left(-3\right)\ldots \}.
故答案为:0.120.1250%50\%1.991.99+6+6(3)-\left(-3\right)3-334-\frac{3}{4}12-123.14-3.1434-\frac{3}{4}0.120.1250%50\%3.14-3.141.991.993-312-1200+6+6(3)-\left(-3\right).

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