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七年级数学解答题一般
题目
(1)(1)已知a=5|a|=5,b=3|b|=3.
①若ab<0ab \lt 0,求a+ba+b的值;
②若a+b=a+b|a+b|=a+b,求aba-b的值;
(2)(2)a1|a-1|b2|b-2|互为相反数,求a+ba+b的值.
知识点:绝对值(二)、绝对值的性质、非负数的性质:偶次方章节:第1章 有理数 / 1.2 有理数 / 1.2.4 绝对值

答案与解析

答案

(1)①a=5\because |a|=5b=3|b|=3
a=±5\therefore a=\pm 5b=±3b=\pm 3
ab<0\because ab \lt 0
a=5\therefore a=5b=3b=-3a=5a=-5b=3b=3
a=5a=5b=3b=-3时,a+b=53=2a+b=5-3=2
a=5a=-5b=3b=3时,a+b=5+3=2a+b=-5+3=-2
a+b\therefore a+b的值为±2\pm 2
a+b=a+b\because |a+b|=a+b
a+b0\therefore a+b\geqslant 0
a=5\because |a|=5b=3|b|=3
a=±5\therefore a=\pm 5b=±3b=\pm 3
a=5\therefore a=5b=±3b=\pm 3
\thereforea=5a=5b=3b=3时,ab=53=2a-b=5-3=2
a=5a=5b=3b=-3时,ab=5(3)=8a-b=5-\left(-3\right)=8
ab\therefore a-b的值为2288
(2)(2)由题意a1+b2=0|a-1|+|b-2|=0
a=1\therefore a=1b=2b=2
a+b=1+2=3\therefore a+b=1+2=3.

解析

(1)①a=5\because |a|=5b=3|b|=3
a=±5\therefore a=\pm 5b=±3b=\pm 3
ab<0\because ab \lt 0
a=5\therefore a=5b=3b=-3a=5a=-5b=3b=3
a=5a=5b=3b=-3时,a+b=53=2a+b=5-3=2
a=5a=-5b=3b=3时,a+b=5+3=2a+b=-5+3=-2
a+b\therefore a+b的值为±2\pm 2
a+b=a+b\because |a+b|=a+b
a+b0\therefore a+b\geqslant 0
a=5\because |a|=5b=3|b|=3
a=±5\therefore a=\pm 5b=±3b=\pm 3
a=5\therefore a=5b=±3b=\pm 3
\thereforea=5a=5b=3b=3时,ab=53=2a-b=5-3=2
a=5a=5b=3b=-3时,ab=5(3)=8a-b=5-\left(-3\right)=8
ab\therefore a-b的值为2288
(2)(2)由题意a1+b2=0|a-1|+|b-2|=0
a=1\therefore a=1b=2b=2
a+b=1+2=3\therefore a+b=1+2=3.

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