题霸题霸学习平台
← 返回公开题库
七年级数学解答题一般
题目
把下列各数填在相应的括号里
2-2,322\frac{3}{{22}},0.6180.618,20212021,345-3\frac{4}{5},00,+2.01+2.01,8%-8\%,2727,14-14
正整数集合:{______}\{ \_\_\_\_\_\_\ldots \}
正分数集合:{______}\{ \_\_\_\_\_\_\ldots \}
非负数集合:{______}\{ \_\_\_\_\_\_\ldots \}
整数集合:{______}\{ \_\_\_\_\_\_\ldots \}
知识点:绝对值(二)章节:第1章 有理数 / 1.2 有理数 / 1.2.4 绝对值

答案与解析

答案

\because在实数2-2322\frac{3}{{22}}0.6180.61820212021345-3\frac{4}{5}00+2.01+2.018%-8\%272714-14中,
正整数有:202120212727
正分数有:322\frac{3}{{22}}0.6180.618+2.01+2.01
非负数有:322\frac{3}{{22}}0.6180.6182021202100+2.01+2.012727
整数有:2-22021202100272714-14
故答案为:202120212727322\frac{3}{{22}}0.6180.618+2.01+2.01322\frac{3}{{22}}0.6180.6182021202100+2.01+2.0127272-22021202100272714-14.

解析

\because在实数2-2322\frac{3}{{22}}0.6180.61820212021345-3\frac{4}{5}00+2.01+2.018%-8\%272714-14中,
正整数有:202120212727
正分数有:322\frac{3}{{22}}0.6180.618+2.01+2.01
非负数有:322\frac{3}{{22}}0.6180.6182021202100+2.01+2.012727
整数有:2-22021202100272714-14
故答案为:202120212727322\frac{3}{{22}}0.6180.618+2.01+2.01322\frac{3}{{22}}0.6180.6182021202100+2.01+2.0127272-22021202100272714-14.

AI 自由组卷

围绕这道题再组一份练习 →

完整试卷

浏览同年级试卷结构 →