题目已知方程组{5x+y=3ax+5y=4\begin{cases}{5x+y=3}\\ {ax+5y=4}\end{cases}{5x+y=3ax+5y=4与{5x+by=1x−2y=5\begin{cases}{5x+by=1}\\ {x-2y=5}\end{cases}{5x+by=1x−2y=5有相同的解，则aaa，bbb的值为()(\quad)()A.{a=1b=2\begin{cases}{a=1}\\ {b=2}\end{cases}{a=1b=2B.{a=−4b=−6\begin{cases}{a=-4}\\ {b=-6}\end{cases}{a=−4b=−6C.{a=−6b=2\begin{cases}{a=-6}\\ {b=2}\end{cases}{a=−6b=2D.{a=14b=2\begin{cases}{a=14}\\ {b=2}\end{cases}{a=14b=2知识点：同解方程组章节：第5章 二元一次方程组 / 5.4 用加减消元法解二元一次方程组
