题目已知关于xxx，yyy的方程组{2x−3y=4ax+by=2\left\{\begin{array}{l}2x-3y=4\\ ax+by=2\end{array}\right.{2x−3y=4ax+by=2与{3x−5y=6bx+ay=−4\left\{\begin{array}{l}3x-5y=6\\ bx+ay=-4\end{array}\right.{3x−5y=6bx+ay=−4有相同的解，则aaa、bbb的值为()(\quad)()A.{a=−2b=1\left\{\begin{array}{l}a=-2\\ b=1\end{array}\right.{a=−2b=1B.{a=1b=−2\left\{\begin{array}{l}a=1\\ b=-2\end{array}\right.{a=1b=−2C.{a=1b=2\left\{\begin{array}{l}a=1\\ b=2\end{array}\right.{a=1b=2D.{a=−1b=−2\left\{\begin{array}{l}a=-1\\ b=-2\end{array}\right.{a=−1b=−2知识点：解二元一次方程组——加减消元法、同解方程组章节：第5章 二元一次方程组 / 5.4 用加减消元法解二元一次方程组
