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八年级数学解答题一般
题目

计算:a2+3aa2+2a+1÷a+3a+1+a+2a+1\dfrac{a^{2}+3a}{a^{2}+2a+1}\div \dfrac{a+3}{a+1}+\dfrac{a+2}{a+1}.

知识点:实数的运算、整式的混合运算、分式的混合运算、零指数幂、负整数指数幂章节:第18章 分式 / 18.3 分式的加法与减法

答案与解析

答案

a2+3aa2+2a+1÷a+3a+1+a+2a+1\dfrac{a^{2}+3a}{a^{2}+2a+1}\div \dfrac{a+3}{a+1}+\dfrac{a+2}{a+1}

=a(a+3)(a+1)2a+1a+3+a+2a+1=\dfrac{a\left(a+3\right)}{\left(a+1\right)^{2}}\cdot \dfrac{a+1}{a+3}+\dfrac{a+2}{a+1}

=aa+1+a+2a+1=\dfrac{a}{a+1}+\dfrac{a+2}{a+1}

=2a+2a+1=\dfrac{2a+2}{a+1}

=2=2.

解析

a2+3aa2+2a+1÷a+3a+1+a+2a+1\dfrac{a^{2}+3a}{a^{2}+2a+1}\div \dfrac{a+3}{a+1}+\dfrac{a+2}{a+1}

=a(a+3)(a+1)2a+1a+3+a+2a+1=\dfrac{a\left(a+3\right)}{\left(a+1\right)^{2}}\cdot \dfrac{a+1}{a+3}+\dfrac{a+2}{a+1}

=aa+1+a+2a+1=\dfrac{a}{a+1}+\dfrac{a+2}{a+1}

=2a+2a+1=\dfrac{2a+2}{a+1}

=2=2.

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