题目已知:x=3+1x=\sqrt{3}+1x=3+1,y=3−1y=\sqrt{3}-1y=3−1,求x2−2xy+y2x2−y2\dfrac{x^{2}-2xy+y^{2}}{x^{2}-y^{2}}x2−y2x2−2xy+y2的值.知识点:二次根式的性质与化简章节:未标注