题目若二次函数y=x2−3x+2y=x^{2}-3x+2y=x2−3x+2过点(m,3)\left(m,3\right)(m,3),则代数式2m2−6m+2023=______.2m^{2}-6m+2023= \_\_\_\_\_\_.2m2−6m+2023=______.知识点：一次函数的图象章节：未标注
