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九年级数学选择题一般
题目
如图,在平面直角坐标系xOyxOy中,点C1C_{1},C2C_{2},\ldots,都在yy轴正半轴上,点A1A_{1}在二次函数y=x2(x>0)y=x^{2}(x \gt 0)图象上,以OA1OA_{1},OC1OC_{1}为邻边作平行四边形OA1B1C1OA_{1}B_{1}C_{1},且OC1=2OA1OC_{1}=\sqrt{2}OA_{1},延长C1B1C_{1}B_{1}与二次函数y=x2(x>0)y=x^{2}(x \gt 0)图象交于点A2A_{2};以C1A2C_{1}A_{2},C1C2C_{1}C_{2}为邻边作平行四边形C1A2B2C2C_{1}A_{2}B_{2}C_{2},且C1C2=2C1A2C_{1}C_{2}=\sqrt{2}C_{1}A_{2},延长C2B2C_{2}B_{2}与二次函数y=x2(x>0)y=x^{2}(x \gt 0)图象交于点A3A_{3}\ldots;按此规律进行下去,若A1A_{1}的横坐标为11,则A2022A_{2022}的坐标为( )
A.
(2021(202120212)2021^{2})
B.
(2021(202120222)2022^{2})
C.
(2022(202220222)2022^{2})
D.
(2023(202320232)2023^{2})
知识点:点的坐标章节:未标注

答案与解析

答案

C

解析

A2A_{2}A2HyA_{2}H\bot y轴于HH

A1\because A_{1}的横坐标为11A1A_{1}又在y=x2(x>0)y=x^{2}(x \gt 0)图象上,
A1(1,1)\therefore A_{1}(1,1)
A1OC1=45\therefore \angle A_{1}OC_{1}=45^{\circ}OA1=12+12=2OA_{1}=\sqrt{1^{2}+1^{2}}=\sqrt{2}
OC1=2OA1=2\therefore OC_{1}=\sqrt{2}OA_{1}=2
\because四边形OA1B1C1OA_{1}B_{1}C_{1}是平行四边形,
B1C1\therefore B_{1}C_{1}OA1OA_{1}
A2C1H=A1OC1=45\therefore \angle A_{2}C_{1}H=\angle A_{1}OC_{1}=45^{\circ}
A2HC1\therefore \triangle A_{2}HC_{1}是等腰直角三角形,
HC1=HA2\therefore HC_{1}=HA_{2}
A2A_{2}的坐标是(a(aa2)a^{2})
a22=a\therefore a^{2}-2=a
a=2\therefore a=2a=1(舍去)a=-1(舍去)
A2\therefore A_{2}的坐标是(2,4)\left(2,4\right)
同理可求A3A_{3}的坐标是(3,9)\left(3,9\right)
A1(1\therefore A_{1}(112)1^{2})A2(2A_{2}(222)2^{2})A3(3A_{3}(332)3^{2})\ldots \ldots
A2022\therefore A_{2022}的坐标是(2022(202220222)2022^{2}).
故选:CC.

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