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七年级数学填空题一般
题目
(x+y)\left(x+y\right)看成一个整体,式子3(x+y)27(x+y)+8(x+y)2+5(x+y)3\left(x+y\right)^{2}-7\left(x+y\right)+8\left(x+y\right)^{2}+5\left(x+y\right)可以化简为______.
知识点:通分章节:未标注

答案与解析

答案

3(x+y)27(x+y)+8(x+y)2+5(x+y)3\left(x+y\right)^{2}-7\left(x+y\right)+8\left(x+y\right)^{2}+5\left(x+y\right)
=(3+8)(x+y)2+(7+5)(x+y)=\left(3+8\right)\left(x+y\right)^{2}+\left(-7+5\right)\left(x+y\right)
=11(x+y)22(x+y)=11\left(x+y\right)^{2}-2\left(x+y\right)
故答案为:11(x+y)22(x+y)11\left(x+y\right)^{2}-2\left(x+y\right).

解析

3(x+y)27(x+y)+8(x+y)2+5(x+y)3\left(x+y\right)^{2}-7\left(x+y\right)+8\left(x+y\right)^{2}+5\left(x+y\right)
=(3+8)(x+y)2+(7+5)(x+y)=\left(3+8\right)\left(x+y\right)^{2}+\left(-7+5\right)\left(x+y\right)
=11(x+y)22(x+y)=11\left(x+y\right)^{2}-2\left(x+y\right)
故答案为:11(x+y)22(x+y)11\left(x+y\right)^{2}-2\left(x+y\right).

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