题目小明同学用S2=110[(x1−8)2+(x2−8)2+⋯+(x10−8)2]S^2=\frac{1}{10}[(x_1-8)^2+(x_2-8)^2+⋯+(x_{10}-8)^2]S2=101[(x1−8)2+(x2−8)2+⋯+(x10−8)2]计算一组数据x1x_{1}x1,x2…x_{2}\ldotsx2…,x10x_{10}x10方差,那么x1+x2+⋯+x10=______.x_{1}+x_{2}+\cdots +x_{10}=\_\_\_\_\_\_.x1+x2+⋯+x10=______.知识点：方差章节：未标注
