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八年级数学填空题一般
题目
用科学计算器求得271271,315315,263263,289289,300300,277277,286286,293293,297297,280280的平均数为______,,方差为______(精确到0.1)0.1).
知识点:计算器——标准差与方差、计算器——平均数章节:第6章 数据的分析 / 6.4 数据的离散程度

答案与解析

答案

由题意知,数据的平均数=110(271+315+263+289+300+277+286+293+297+280)=287.1=\frac{1}{10}(271+315+263+289+300+277+286+293+297+280)=287.1
方差S2=110[(271287.1)2+(315287.1)2+(263287.1)2+(289287.1)2+(300287.1)2+(277287.1)2+(286287.1)2+(293287.1)2+(297287.1)2+(280287.1)2]=207.4S^{2}=\frac{1}{10}[\left(271-287.1\right)^{2}+\left(315-287.1\right)^{2}+\left(263-287.1\right)^{2}+\left(289-287.1\right)^{2}+\left(300-287.1\right)^{2}+\left(277-287.1\right)^{2}+\left(286-287.1\right)^{2}+\left(293-287.1\right)^{2}+\left(297-287.1\right)^{2}+\left(280-287.1\right)^{2}]=207.4.
故答案为:287.1287.1207.4207.4.

解析

由题意知,数据的平均数=110(271+315+263+289+300+277+286+293+297+280)=287.1=\frac{1}{10}(271+315+263+289+300+277+286+293+297+280)=287.1
方差S2=110[(271287.1)2+(315287.1)2+(263287.1)2+(289287.1)2+(300287.1)2+(277287.1)2+(286287.1)2+(293287.1)2+(297287.1)2+(280287.1)2]=207.4S^{2}=\frac{1}{10}[\left(271-287.1\right)^{2}+\left(315-287.1\right)^{2}+\left(263-287.1\right)^{2}+\left(289-287.1\right)^{2}+\left(300-287.1\right)^{2}+\left(277-287.1\right)^{2}+\left(286-287.1\right)^{2}+\left(293-287.1\right)^{2}+\left(297-287.1\right)^{2}+\left(280-287.1\right)^{2}]=207.4.
故答案为:287.1287.1207.4207.4.

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