题目(1)(1)(1)计算:ab+ca+b+a2−ca+b\dfrac{ab+c}{a+b}+\dfrac{{{a}^{2}}-c}{a+b}a+bab+c+a+ba2−c (2)(2)(2)解方程:2xx−2=1−12−x\dfrac{2x}{x-2}=1-\dfrac{1}{2-x}x−22x=1−2−x1 (3)(3)(3)先化简:(a−2a−1a)÷1−a2a2+a(a-\dfrac{2a-1}{a})\div \dfrac{1-{{a}^{2}}}{{{a}^{2}}+a}(a−a2a−1)÷a2+a1−a2,然后从000,111,222中选一个你认为合适的aaa值代入求值。知识点:解分式方程,分式的化简求值章节:未标注