题目解方程：(1)3x+2=1x+1(1)\dfrac{3}{x+2}=\dfrac{1}{x+1}(1)x+23=x+11； (2)x−8x−7−17−x=8(2)\dfrac{x-8}{x-7}-\dfrac{1}{7-x}=8(2)x−7x−8−7−x1=8．知识点：解分式方程章节：未标注
