题目在Rt△ABCRt\triangle ABCRt△ABC中,∠C=90∘\angle C=90^{\circ}∠C=90∘,ADADAD平分∠BAC\angle BAC∠BAC交BCBCBC于点DDD,若BC=32BC=32BC=32,且BD:DC=9:7BD:DC=9:7BD:DC=9:7,则点DDD到ABABAB边的距离为（ ）A.181818B.161616C.141414D.121212知识点：角平分线的性质章节：未标注
