题目如图,ABABAB是⊙O\odot O⊙O的直径,点CCC在⊙O\odot O⊙O上,CD⊥ABCD\bot ABCD⊥AB,垂足为DDD,∠ACD\angle ACD∠ACD的平分线交ABABAB于点EEE,交⊙O\odot O⊙O于点FFF.若⊙O\odot O⊙O的直径为666,BE=2BE=2BE=2,则AFAFAF的长为______.知识点:切线的判定章节:图形的性质 / 圆