题目如图,射线OCOCOC是∠AOB\angle AOB∠AOB的角平分线,DDD是射线OCOCOC上一点,DP⊥OADP\bot OADP⊥OA于点PPP,DP=4DP=4DP=4,若点QQQ是射线OBOBOB上一点,OQ=3OQ=3OQ=3,则△ODQ\triangle ODQ△ODQ的面积是( )A.333B.444C.555D.666知识点:垂线段最短章节:未标注