题目如图,EEE,FFF两点分别在正方形ABCDABCDABCD的边BCBCBC,CDCDCD上,BE=2CEBE=2CEBE=2CE,沿AEAEAE折叠△ABE\triangle ABE△ABE,沿AFAFAF折叠△ADF\triangle ADF△ADF,使得BBB,DDD两点重合于点GGG.且EEE,GGG,FFF在同一条直线上,则DFCD\frac{DF}{CD}CDDF的值为( )A.25\frac{\sqrt{2}}{5}52B.15\frac{1}{5}51C.16\frac{1}{6}61D.26\frac{\sqrt{2}}{6}62知识点:四边形综合题章节:图形的性质 / 四边形