题目如图,∠AOC=∠BOD=90∘\angle AOC=\angle BOD=90^{\circ}∠AOC=∠BOD=90∘,∠AOD=126∘\angle AOD=126^{\circ}∠AOD=126∘,则∠BOC\angle BOC∠BOC的大小为( )A.36∘36^{\circ}36∘B.44∘44^{\circ}44∘C.54∘54^{\circ}54∘D.63∘63^{\circ}63∘知识点:余角和补角章节:未标注