题目解不等式组:{x+52＜3x3x−4＞2(x+1)\left\{\begin{array}{l}{\frac{x+5}{2}＜3x}\\{3x-4＞2(x+1)}\end{array}\right.{2x+5＜3x3x−4＞2(x+1).知识点：解二元一次方程组——代入消元法章节：未标注
