题目如图,在Rt△ABCRt\triangle ABCRt△ABC中,∠ACB=90∘\angle ACB=90^{\circ}∠ACB=90∘,∠A=60∘\angle A=60^{\circ}∠A=60∘,AC=4AC=4AC=4,将△CAB\triangle CAB△CAB绕点CCC按逆时针方向旋转得到△CDE\triangle CDE△CDE,点DDD恰好在ABABAB边上,连接BEBEBE,则BEBEBE的长为( )A.888B.424\sqrt{2}42C.434\sqrt{3}43D.666知识点:角的运算章节:未标注