题目如图,△ABC\triangle ABC△ABC中,∠ABC=3∠C\angle ABC=3\angle C∠ABC=3∠C,点DDD,EEE分别在边BCBCBC,ACACAC上,∠EDC=24∘\angle EDC=24^{\circ}∠EDC=24∘,∠ADE=3∠AED\angle ADE=3\angle AED∠ADE=3∠AED,∠ABC\angle ABC∠ABC的平分线与∠ADE\angle ADE∠ADE的平分线交于点FFF,则∠F\angle F∠F的度数是( )A.54∘54^{\circ}54∘B.60∘60^{\circ}60∘C.66∘66^{\circ}66∘D.72∘72^{\circ}72∘知识点:角的运算章节:图形的性质 / 图形认识初步