题目(1)(1)(1)计算:−32+∣3−2∣+(13)−2−23−1-3^2+|\sqrt{3}-2|+(\frac{1}{3})^{-2}-\frac{2}{\sqrt{3}-1}−32+∣3−2∣+(31)−2−3−12；(2)(2)(2)解不等式组:{2x+1＞3(x−1)2x−12≤4−2x3\left\{\begin{array}{l}2x+1＞3(x-1)\\ \frac{2x-1}{2}≤\frac{4-2x}{3}\end{array}\right.{2x+1＞3(x−1)22x−1≤34−2x；(3)(3)(3)解方程:x2−6x+4=0x^{2}-6x+4=0x2−6x+4=0；(4)(4)(4)解方程:(x−3)2=2x(x−3)\left(x-3\right)^{2}=2x\left(x-3\right)(x−3)2=2x(x−3).知识点：解一元一次不等式组章节：方程与不等式 / 不等式与不等式组
