题目(1)(1)(1)因式分解:x2y−2xy2+y3x^{2}y-2xy^{2}+y^{3}x2y−2xy2+y3(2)(2)(2)解不等式组:{5x−1＜3(x+1)x−12＞x3−1\left\{\begin{array}{l}{5x-1＜3(x+1)}\\{\frac{x-1}{2}＞\frac{x}{3}-1}\end{array}\right.{5x−1＜3(x+1)2x−1＞3x−1知识点：在数轴上表示不等式的解集章节：方程与不等式 / 不等式与不等式组
