题目如图,PAPAPA,PBPBPB切⊙O\odot O⊙O于AAA,BBB两点,CDCDCD切⊙\odot⊙于点EEE,交PAPAPA、PBPBPB于CCC、DDD,若△PCD\triangle PCD△PCD的周长等于444,则线段PAPAPA的长是( )A.444B.888C.222D.111知识点:切线长定理章节:未标注