题目如图,在△ABC\triangle ABC△ABC中,DDD是ABABAB上一点,DFDFDF交ACACAC于EEE,DE=EFDE=EFDE=EF,AE=ECAE=ECAE=EC,则下列说法中,①∠ADE=∠EFC\angle ADE=\angle EFC∠ADE=∠EFC;②∠ADE+∠ECF+∠FEC=180∘\angle ADE+\angle ECF+\angle FEC=180^{\circ}∠ADE+∠ECF+∠FEC=180∘;③∠B+∠BCF=180∘\angle B+\angle BCF=180^{\circ}∠B+∠BCF=180∘;④S△ABC=S四边形DBCFS_{\triangle ABC}=S_{四边形DBCF}S△ABC=S四边形DBCF.正确的说法个数有( )A.444个B.333个C.222个D.111个知识点:相似三角形的判定I章节:未标注