题目方程x2−x=0x^{2}-x=0x2−x=0的解是( )A.x1=x2=0x_{1}=x_{2}=0x1=x2=0B.x1=0x_{1}=0x1=0,x2=−1x_{2}=-1x2=−1C.x1=x2=1x_{1}=x_{2}=1x1=x2=1D.x1=0x_{1}=0x1=0,x2=1x_{2}=1x2=1知识点:解一元二次方程——因式分解法章节:方程与不等式 / 一元二次方程