题目如图,CDCDCD是⊙O\odot O⊙O的直径,点AAA,BBB在⊙O\odot O⊙O上.若AC^=BC^\widehat {AC}=\widehat {BC}AC=BC,∠AOC=36∘\angle AOC=36^{\circ}∠AOC=36∘,则∠D=( )\angle D=\left(\ \ \right)∠D=( )A.9∘9^{\circ}9∘B.18∘18^{\circ}18∘C.36∘36^{\circ}36∘D.45∘45^{\circ}45∘知识点:切线的性质章节:图形的性质 / 圆