题目用"☆"定义一种新运算:对于任何不为零的整数aaa和bbb,规定aaa☆b=a2−b2b=a^{2}-b^{2}b=a2−b2,如(−1)\left(-1\right)(−1)☆2=(−1)2−22=−32=\left(-1\right)^{2}-2^{2}=-32=(−1)2−22=−3,则(−3)\left(-3\right)(−3)☆(−1)\left(-1\right)(−1)的值为( )A.−8-8−8B.888C.38\frac{3}{8}83D.−38-\frac{3}{8}−83知识点:去括号与添括号章节:数与式 / 代数式