题目如图,△AOB,\triangle AOB,△AOB≌△ADC,∠O=∠D=90∘\triangle ADC,\angle O=\angle D=90^{\circ}△ADC,∠O=∠D=90∘,记∠OAD=α\angle OAD=\alpha∠OAD=α,∠ABO=β\angle ABO=\beta∠ABO=β,当BCBCBC∥OAOAOA时,α\alphaα与β\betaβ之间的数量关系为( )A.α=β\alpha =\betaα=βB.α=2β\alpha =2\betaα=2βC.α+β=90∘\alpha +\beta =90^{\circ}α+β=90∘D.α+2β=180∘\alpha +2\beta =180^{\circ}α+2β=180∘知识点:平行线的性质章节:图形的性质 / 相交线与平行线