题目已知m>nm \gt nm>n,下列不等式一定成立的是（ ）A.am>anam \gt anam>anB.ma＞na\frac{m}{a}＞\frac{n}{a}am＞anC.(a2−1)m>(a2−1)n(a^{2}-1)m \gt (a^{2}-1)n(a2−1)m>(a2−1)nD.(a2+1)m>(a2+1)n(a^{2}+1)m \gt (a^{2}+1)n(a2+1)m>(a2+1)n知识点：不等式的性质章节：方程与不等式 / 不等式与不等式组
