题目根据“xxx的333倍与555的和比xxx的15\dfrac{1}{5}51多222”可列方程()(\quad)()A.3x+5=x5−23x+5=\dfrac{x}{5}-23x+5=5x−2B.3x+5=x5+23x+5=\dfrac{x}{5}+23x+5=5x+2C.3(x+5)=x5−23(x+5)=\dfrac{x}{5}-23(x+5)=5x−2D.3(x+5)=x5+23(x+5)=\dfrac{x}{5}+23(x+5)=5x+2知识点:由实际问题抽象出一元一次方程章节:方程与不等式 / 一元一次方程