题目已知半径为333的⊙O\odot O⊙O中,弦AB=32AB=3\sqrt{2}AB=32,弦AC=3AC=3AC=3,则∠BAC=______∘.\angle BAC= \_\_\_\_\_\_^{\circ}.∠BAC=______∘.知识点：切线的性质章节：图形的性质 / 圆
