题目如图,PAPAPA,PBPBPB是⊙O\odot O⊙O的切线,AAA,BBB为切点,∠PAB=52∘\angle PAB=52^{\circ}∠PAB=52∘,则∠P=______∘.\angle P=\_\_\_\_\_\_^{\circ}.∠P=______∘.知识点：切线长定理章节：图形的性质 / 圆
如图,,是的切线,,为切点,,则如图,,是的切线,,为切点,,则如图,,是的切线,,为切点,,则