题目如图,四边形ABCDABCDABCD内接于⊙O\odot O⊙O,∠ABC=135∘\angle ABC=135^{\circ}∠ABC=135∘,AC=4AC=4AC=4,则⊙O\odot O⊙O的半径为( )A.444B.222\sqrt{2}22C.3\sqrt{3}3D.424\sqrt{2}42知识点:垂径定理章节:图形的性质 / 圆