题目如图,ABABAB是⊙O\odot O⊙O的直径,弦CD⊥ABCD\bot ABCD⊥AB于点EEE,若BE=5BE=5BE=5,AE=1AE=1AE=1,则弦CDCDCD的长是( )A.555B.5\sqrt{5}5C.252\sqrt{5}25D.666知识点:垂径定理章节:图形的性质 / 圆