题目某玩具店用600060006000元购进甲、乙两种陀螺,甲种单价比乙种单价便宜555元,单独买甲种比单独买乙种可多买404040个.设甲种陀螺单价为xxx元,根据题意列方程为( )A.6000x=6000x−5+40\dfrac{6000}{x}=\dfrac{6000}{x-5}+40x6000=x−56000+40B.6000x=6000x−5−40\dfrac{6000}{x}=\dfrac{6000}{x-5}-40x6000=x−56000−40C.6000x=6000x+5+40\dfrac{6000}{x}=\dfrac{6000}{x+5}+40x6000=x+56000+40D.6000x=6000x+5−40\dfrac{6000}{x}=\dfrac{6000}{x+5}-40x6000=x+56000−40知识点:由实际问题抽象出分式方程章节:方程与不等式 / 分式方程